ozzy23padilla
Answered

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The two plates of a capacitor hold +2.5 x 10-3 C and
-2.5 x 10-3 C of charge when the potential difference is
950 V. What is the capacitance?

Sagot :

Answer:

2.63 microfarads

Explanation:

C = Q/V   =  2.5 x 10^-3 C / 950 V = 2.63 microfarads

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