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Sagot :
Answer:
d) 303 8/9
Step-by-step explanation:
4th term = ar^3 and 5th = ar^4 where a = first term and r = common ratio.
So ar^4 / ar^3
= r = 45/-15 = -3.
Working back,:
The first term a = ar^3/ r^3
= -15 / (-3)^3
= -15/-27
= 5/9
Sum of n terms = a * (r^n - 1)/(r-1)
= 5/9 * ((-3)^7 - 1 ) / (-3 -1)
= 303 8/9
Is the 4th term is -15 and the 5th term is 45, then you would set it up like a5=a4(r)^5-4
45=-15(r)^1
Then you would get -3=r so the common ratio is -3, then you have to solve for a1 which would copy the previous format like -15=a1(-3)^3 which would be
(5/9). The formula for a geometric sequence is an=a1(r)^n-1
The formula for a limited geometric sequence is Sn=a1((1-r^n)/(1-r))
(5/8)((1-(-3)^7)/(1-(-3))
(5/9)(16385/5)
2735/9=303 8/9
So D!
45=-15(r)^1
Then you would get -3=r so the common ratio is -3, then you have to solve for a1 which would copy the previous format like -15=a1(-3)^3 which would be
(5/9). The formula for a geometric sequence is an=a1(r)^n-1
The formula for a limited geometric sequence is Sn=a1((1-r^n)/(1-r))
(5/8)((1-(-3)^7)/(1-(-3))
(5/9)(16385/5)
2735/9=303 8/9
So D!
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