Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

In 1991, the population of Melonville was a square number. In 1992, with an increase of 100, the population became 1 greater than a perfect square. In 1993, with another increase of 100, the population again became a perfect square. Find the population of Melonville in 1993.

Sagot :

MrRoyal

The population of Melonville follows a population growth, and the population of Melonville in 1993 is 201

How to determine the population?

Let the population in 1991 be x².

The 1992 population is

P₂ = y² + 1 = x² + 100

This means that:

x² + 100 = y² + 1

Rewrite as:

y² - x² = 100 - 1

y² - x² = 99

Express as difference of two squares

(y - x)(y + x) = 99

Express 99 as 9 * 11

(y - x)(y + x) = 9 * 11

Rewrite as:

(y - x)(y + x) = (10 - 1) * (10 + 1)

By comparison, we have:

y = 10 and x = 1

So, the populations are:

P₁ = x² --- 1991

P₂ = x² + 100 --- 1992

P₃ = x² +100 +100 --- 1993

Substitute 1 for x

P₃ = 1² +100 +100

Evaluate

P₃ = 201

Hence, the population of Melonville in 1993 is 201

Read more about population growth at:

https://brainly.com/question/20115298

#SPJ1

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.