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Prove: ln |tan θ| = ln |sin θ| − ln | cos θ|

Sagot :

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Answer:

Step-by-step explanation:

We use the law of logarithms that says log A - log B = log (A/B)

ln |sin θ| − ln | cos θ| =  ln |sin θ/ cos θ|

We use that the tan A = sin A/cosB

ln |sin θ/ cos θ| = ln |tan θ|

ln |tan θ| = ln |sin θ| − ln | cos θ|

ln |tan θ| = ln |sin θ/ cos θ|

ln |tan θ| = ln |tan θ|

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