Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The time period for which the rocket is in the air will be 1.408 sec. The equation of motion is used to solve the problem.
What is the time period?
The total time period is the sum of the time required to move upwards and the time required to move downwards.
The height attained by the rocket is found as;
[tex]\rm v^2 = u^2 -2gh \\\\ \rm u^2= 2gh \\\\ h=\frac{u^2}{2g} \\\\ h=\frac{(24\times 0.3048)^2}{2\times 9.81 } \\\\ h=2.72 \ m[/tex]
The time for the rocket in the air is found as;
[tex]\rm v= u+gt \\\\ \rm t = \frac{v-u}{g} \\\\ t = \frac{0-24 \times 0.3048 }{-9.81} \\\\ t= 0.704\sec\\\\ T=2\times t \\\\ T= 2\times 0.704 \\\\ T=1.408 \ sec[/tex]
Hence, the time period for which the rocket is in the air will be 1.408 sec.
To learn more about the time period, refer to the link;
https://brainly.com/question/569003
#SPJ1
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.
