The time period for which the rocket is in the air will be 1.408 sec. The equation of motion is used to solve the problem.
The total time period is the sum of the time required to move upwards and the time required to move downwards.
The height attained by the rocket is found as;
[tex]\rm v^2 = u^2 -2gh \\\\ \rm u^2= 2gh \\\\ h=\frac{u^2}{2g} \\\\ h=\frac{(24\times 0.3048)^2}{2\times 9.81 } \\\\ h=2.72 \ m[/tex]
The time for the rocket in the air is found as;
[tex]\rm v= u+gt \\\\ \rm t = \frac{v-u}{g} \\\\ t = \frac{0-24 \times 0.3048 }{-9.81} \\\\ t= 0.704\sec\\\\ T=2\times t \\\\ T= 2\times 0.704 \\\\ T=1.408 \ sec[/tex]
Hence, the time period for which the rocket is in the air will be 1.408 sec.
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