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Sagot :
Answer:
Given:-
The algebraic form of an arithmetic sequence is 4n+1.
To find:-
common difference.
first term
remainder when each term of the sequence is divided by 4.
Solution:-
Given,
and n = 1,2,3...
Now,
If n = 2,
The sequence is 5 ,9,13..
Hence, the first term is 5.
Common difference :
=> d =
=> 9- 5
=> d = 4.
Hence, common difference is 4.
Remainder :
=> 5/4 = 4(4) +1
Here, remainder =1
=> 9/4 = 4(2)+1
Here, remainder =1
=> 13/4 = 4 (3)+1
Here , remainder = 1.
Therefore, the remainder when each term of this sequence is divided by 4 is 1 .
Step-by-step explanation:
Answer:
Below in bold.
Step-by-step explanation:
The nth term = a + d(n - 1) where a = first term and d = common difference
= dn + a - d
So comparing this to 4n + 1:
a) d = 4
b) a - d = a - 4 = 1
so a first term = 5.
c) (4n + 1) / 4 = n remainder 1
The remainder is 1.
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