stephenasselin80
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Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

Sagot :

semsee45

Answer:

**The equation is not clear, so I have provided both options**

Option 1

[tex]\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2[/tex]

[tex]\implies \left|0.3-\dfrac{3}{5}k\right|=1.6[/tex]

Solution 1

[tex]\implies 0.3-\dfrac{3}{5}k=1.6[/tex]

[tex]\implies -\dfrac{3}{5}k=1.3[/tex]

[tex]\implies k=-\dfrac{13}{6}[/tex]

Solution 2

[tex]\implies -(0.3-\dfrac{3}{5}k)=1.6[/tex]

[tex]\implies -0.3+\dfrac{3}{5}k=1.6[/tex]

[tex]\implies \dfrac{3}{5}k=1.9[/tex]

[tex]\implies k=\dfrac{19}{6}[/tex]

Option 2

[tex]\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2[/tex]

[tex]\implies \left|0.3-\dfrac{3}{5k}\right|=1.6[/tex]

Solution 1

[tex]\implies 0.3-\dfrac{3}{5k}=1.6[/tex]

[tex]\implies -\dfrac{3}{5k}=1.3[/tex]

[tex]\implies -3=6.5k[/tex]

[tex]\implies k=-\dfrac{6}{13}[/tex]

Solution 2

[tex]\implies -(0.3-\dfrac{3}{5k})=1.6[/tex]

[tex]\implies -0.3+\dfrac{3}{5k}=1.6[/tex]

[tex]\implies \dfrac{3}{5k}=1.9[/tex]

[tex]\implies 3=9.5k[/tex]

[tex]\implies k=\dfrac{6}{19}[/tex]

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