Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by the equation graphed below, where m = 0 represents january 1, m = 1 represents february 1, m = 2 represents march 1, and so on. if the equation is t = a cosine (startfraction pi over 6 endfraction (m 1)) k, what are the values of a and k?

Sagot :

abidemiokin

The equivalent expression for the function is given as [tex]t=-35sin(\frac{\pi}{6}m +55)\\[/tex]

Sine and cosine functions

Given the average daily temperature of a city expressed acccording to the cosine function

[tex]t=35cos(\frac{\pi}{6} (m+3))+55[/tex]

In order to rewrite as a function of sine, first expand the parenthesis to have:

[tex]t=35cos(\frac{\pi}{6}m +3(\frac{\pi}{6} ))+55\\t=35cos(\frac{\pi}{6}m +\frac{\pi}{2} )+55\\[/tex]

Recall from trigonometry identity that:

cos(x+90ā°)=-sin(x)

The equivalent expression for the function is given as:

[tex]t=-35sin(\frac{\pi}{6}m +55)\\[/tex]

Learn more on trigonometry functions here: https://brainly.com/question/1143565

#SPJ4

View image abidemiokin

Answer:

A

Step-by-step explanation:

t--35 sin(m) + +55

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.