Narwhal0411
Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

80 POINTS! NO LINKS

How much ribbon would be needed to go around a package that had a length 2x^2+3x-5/x^2+x-3 centimeters and width x^2-x-5/x^2+x-3 centimeters?

80 POINTS NO LINKS How Much Ribbon Would Be Needed To Go Around A Package That Had A Length 2x23x5x2x3 Centimeters And Width X2x5x2x3 Centimeters class=

Sagot :

raphealnwobi

The amount of ribbon needed to go around a package that had a length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) is

[tex]\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}[/tex]

What is an equation?

An equation is an expression that shows the relationship between two or more number and variables.

The  length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) centimeters. Hence:

[tex]Area=\frac{2x^2+3x-5}{x^2+x-3} *\frac{x^2-x-5}{x^2+x-3} =\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}[/tex]

The amount of ribbon needed to go around a package that had a length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) is

[tex]\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}[/tex]

Find out more on equation at: https://brainly.com/question/2972832

#SPJ1

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.