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How much ribbon would be needed to go around a package that had a length 2x^2+3x-5/x^2+x-3 centimeters and width x^2-x-5/x^2+x-3 centimeters?

80 POINTS NO LINKS How Much Ribbon Would Be Needed To Go Around A Package That Had A Length 2x23x5x2x3 Centimeters And Width X2x5x2x3 Centimeters class=

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The amount of ribbon needed to go around a package that had a length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) is

[tex]\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}[/tex]

What is an equation?

An equation is an expression that shows the relationship between two or more number and variables.

The  length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) centimeters. Hence:

[tex]Area=\frac{2x^2+3x-5}{x^2+x-3} *\frac{x^2-x-5}{x^2+x-3} =\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}[/tex]

The amount of ribbon needed to go around a package that had a length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) is

[tex]\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}[/tex]

Find out more on equation at: https://brainly.com/question/2972832

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