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Find the sum of the first 8 terms of the following series, to the nearest integer.
80,20,5,...

Sagot :

nuhulawal20

The sum of the first 8 terms of the geometric series ( 80, 20, 5, ... ) to the nearest integer is 1747600.

What is the Sum of the first 8 terms of the geometric sequence?

Using the formula;

Sn = a₁ *  ( (1-rⁿ)/(1-r) )

Given that;

80,20,5,...

  • nth term n  = 8
  • First value a₁ = 80
  • Common ratio r = 4

We substitute our values into the expression above.

Sn = a₁ ×  ( (1-rⁿ)/(1-r) )

Sn = 80 × ( (1-4⁸)/(1-4) )

Sn = 80 × ( (1-65536)/(1-4) )

Sn = 80 × ( -65535 / -3 )

Sn = 80 × 21845

Sn = 1747600

Therefore, the sum of the first 8 terms of the geometric series ( 80, 20, 5, ... ) to the nearest integer is 1747600.

Learn more about geometric series here: https://brainly.com/question/19458543

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