jessekwasiafful
Answered

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A cylindrical water bottle is 28cm in diameter. How much is the water level lowered when 1 litre is drawn off? Take π=22/7​

Sagot :

s1m1

Answer:

h = 1/616 ≈.002 cm

Step-by-step explanation:

V of a cylinder = Area of the circle · height of the cylinder

A of the circle = π·r² = π·(d/2)² = (22/7)·(28/2)² = 616 cm³

If the V of the cylinder = 1 liter and the Area of the circle  = 616 cm³ then

What is the height of the cylinder?

                             V of a cylinder = Area of the circle · height of the cylinder

V of a cylinder / Area of the circle = height of the cylinder

                                                1/616 = height of the cylinder

Height of the cylinder that is lowered when 1 liter of water is drawn is  

h = 1/616 ≈.002 cm

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