Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

If f(x) = 2x^2 – 3x + 1 and g(x) = x + 1, then
f(g(x)) =

Sagot :

loneguy

[tex]\text{Given that,}~ f(x) =2x^2 -3x +1~ \text{and}~ g(x) = x+1[/tex]

[tex]f(g(x))\\\\=f(x+1)\\\\=2(x+1)^2 -3(x+1) +1\\\\=2(x^2 +2x +1) -3x -3 +1\\\\=2x^2 +4x +2-3x -2\\\\=2x^2 +x\\\\=x(2x+1)[/tex]

s1m1

Answer:

f(g(x)) = 2x² + x

Step-by-step explanation:

f(x) = 2x² – 3x + 1 and g(x) = x + 1

→substitute  g(x)  for  x + 1

f(g(x)) = f (x + 1)

→substitute x for x+1 into the f(x) equation

f(g(x)) = f (x + 1)  = 2(x+1)² – 3(x+1) + 1

→calculate

f(g(x)) =  2(x+1)² – 3(x+1) + 1 , square x+1

f(g(x)) = 2( x²+2x+1) -3(x+1) +1 , distribute in parenthesis

f(g(x)) = 2x²+4x+2 -3x -3 +1, combine like terms

f(g(x)) = 2x² + x

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.