Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.


[tex] ({4e }^{2} + 16e - 9) \div (2ef + 12e - f - 6)[/tex]
please help me solve this problem​


Sagot :

Explanation

[tex]\dfrac{4e^2+16e-9}{2ef+12e-f-6}[/tex]

⇒ First, factor the numerator by grouping:

[tex]=\dfrac{4e^2-2e+18e-9}{2ef+12e-f-6}\\\\\\=\dfrac{2e(2e-1)+9(2e-1)}{2ef+12e-f-6}\\\\\\=\dfrac{(2e+9)(2e-1)}{2ef+12e-f-6}[/tex]

⇒ Now, factor the denominator by grouping:

[tex]=\dfrac{(2e+9)(2e-1)}{2e(f+6)-(f+6)}\\\\\\=\dfrac{(2e+9)(2e-1)}{(2e-1)(f+6)}[/tex]

We must determine which values of e and f are unacceptable, meaning, will make this expression undefined. These will be the values of e and f that make the denominator equal to 0.

  • ⇒ To find these values, let's set each term in the denominator equal to 0, and solve for e and f.
  • [tex]2e-1=0[/tex] ⇒ [tex]2e=1[/tex] [tex]e=\dfrac{1}{2}[/tex]
  • [tex]f+6=0[/tex] ⇒ [tex]f=-6[/tex]
  • ⇒ The restrictions for e and f include [tex]e=\dfrac{1}{2}[/tex] and [tex]f=-6[/tex].

[tex]=\dfrac{(2e+9)(2e-1)}{(2e-1)(f+6)}[/tex]

⇒ Reduce values in the numerator and denominator:

[tex]=\dfrac{(2e+9)}{(f+6)}\\\\\\=\dfrac{2e+9}{f+6}[/tex]

Answer

[tex]=\dfrac{2e+9}{f+6}[/tex]