Answer:
[tex]x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}[/tex]
or
[tex]x = \frac{\pm4\sqrt{15}}{3}[/tex]
Step-by-step explanation:
Hello!
Use the quadratic formula: [tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
First, let's convert our equation to standard form of a Quadratic: ax² + bx + c = 0
3x² = 80
3x² - 80 = 0
Note, thats the value of b will be 0, as there is no "bx"
Now, solve:
- [tex]x = \frac{-(0) \pm \sqrt{(0)^2 - 4(3)(-80)}}{2(3)}[/tex] Plug in values
- [tex]x = \frac{\pm\sqrt{960}}{6}[/tex] Simplify the radical (Discriminant)
- [tex]x = \frac{\pm8\sqrt{15}}{6}[/tex] Pull out perfect squares
- [tex]x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}[/tex] Reduce factors
The solutions are [tex]x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}[/tex]
