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Sagot :
The figure is an illustration of laws of sines, and the distance from A to B is 2534 feet
How to determine the distance AB?
The given parameters are:
DAB = 25°
L = 1700
ACB = 15°
Start by calculating the measure of angles CAB and ABC
CAB = 180 - DAB
This gives
CAB = 180 - 25°
CAB = 155°
Also, we have:
ABC = 180 - CAB - ACB
ABC = 180 - 155 - 15
ABC = 10°
The length AB is then calculated using the following laws of sines
[tex]\frac{AB}{\sin(C)} = \frac{L}{\sin(B)}[/tex]
This gives
[tex]\frac{AB}{\sin(15)} = \frac{1700}{\sin(10)}[/tex]
Make AB the subject
[tex]AB = \frac{1700}{\sin(10)} *\sin(15)[/tex]
Evaluate
AB = 2533.8151116
Approximate
AB = 2534
Hence, the distance from A to B is 2534 feet
Read more about laws of sines at:
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