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Identify the perimeter of a rectangle in which h=8 ft and A=144x ft2.

Sagot :

princechimezirim096

Answer:

52ft

Step-by-step explanation:

perimeter of a rectangle = 2 (height+ breath)

Area of a rectangle = height× breath

144= 8×L

L= 144/8 = 18ft

perimeter= 2(8+18)

perimeter= 2(26)= 52ft

The width of the rectangle will be 18 feet (5.49 meters). Then the perimeter of the rectangle will be 52 feet (15.85 meters).

What is the perimeter of the rectangle?

Let H be the height and W be the width of the rectangle.

Then the perimeter of the rectangle will be

Perimeter of the rectangle = 2(H + W) units

The area of the rectangle will be 144 square feet (13.38 square meters) and the height of the rectangle is 8 feet (2.44 meters).

Then the area of the rectangle is given as,

A = H x W

144 = 8W

W = 144 / 8

W = 18 feet (5.49 meters)

Then the perimeter of the rectangle will be

P = 2(18 + 8)

P = 2(26)

P = 52 feet (15.85 meters)

The width of the rectangle will be 18 feet (5.49 meters). Then the perimeter of the rectangle will be 52 feet (15.85 meters).

More about the perimeter of the rectangle link is given below.

https://brainly.com/question/15287805

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