Anulakshmi
Answered

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Multiply the additive inverse of (-7/8) by the reciprocal of (5 1/2)​

PLEASE HELP!

Sagot :

devishri1977

Answer:

[tex]\bold {$\dfrac{7}{44}$}[/tex]

Step-by-step explanation:

Reciprocal:

    [tex]\sf \text{The reciprocal of any number $\dfrac{a}{b}$ is given by $\dfrac{b}{a}$}\\\\5\dfrac{1}{2}=\dfrac{11}{2}\\\\\text{Reciprocal of $\dfrac{11}{2}$ = $\dfrac{2}{11}$}[/tex]

Additive inverse:

 [tex]\text{Additive inverse of $\dfrac{-7}{8}$=$\dfrac{7}{8}$}[/tex]

        Now multiply,

          [tex]\sf \dfrac{7}{8}*\dfrac{2}{11}=\dfrac{7}{4}*\dfrac{1}{11}\\[/tex]

                      [tex]=\dfrac{7}{44}[/tex]

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