Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

In ΔJKL, k = 430 cm, l = 590 cm and ∠J=117°. Find the length of j, to the nearest centimeter

Sagot :

defnotmish

Answer:

j²=k²+l²-2klCosJ

j²=430²+590²-2(430)(590)Cos117

j=874cm

Step-by-step explanation:

Use the formula of triangles.

make sure to square root at the second last step where j²=763 354,7797

therefore your answer will be 874cm if you round off correctly to the nearest centimeter.

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.