Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

In ΔJKL, k = 430 cm, l = 590 cm and ∠J=117°. Find the length of j, to the nearest centimeter

Sagot :

defnotmish

Answer:

j²=k²+l²-2klCosJ

j²=430²+590²-2(430)(590)Cos117

j=874cm

Step-by-step explanation:

Use the formula of triangles.

make sure to square root at the second last step where j²=763 354,7797

therefore your answer will be 874cm if you round off correctly to the nearest centimeter.

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.