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A girl weighing 50 kgf wears sandals of pencil heel of area of cross section 1 cm^2, stands on the floor.An elephant weighing 2000 kgf stands on foot each area of cross section 250 cm^2,on the floor.Compare the pressure exerted by two of 'em.​

Sagot :

Itz5151

Answer:

[tex] \boxed{{\boxed{\blue{ 12.5}}}}[/tex]

Explanation:

Given, for girl : Weight or force;

[tex] \rm \: F_1 = 50 \: kgf[/tex]

Area of both heels;

[tex] \rm \: A_1 = \; 2 ×1 \; cm^2 = 2 \: cm^2[/tex]

[tex] \rm \: Pressure \: P_1 = \cfrac{F_1}{ A_1 } = \dfrac{50 \: kgf}{2 \: cm {}^{2} } = 25 \: kgf \: cm {}^{ - 1} [/tex]

For elephant, Weight = Force [tex]\rm F_2 [/tex] = 2000 kg•f

Area of 4 feet;

[tex] \rm \: A_2 = \; 4 \times 250 \; cm^2 = 1000 \: cm^2[/tex]

[tex] \rm \: Pressure \: P_2 = {F_2}/{A_2} \; = \cfrac{2 \cancel{0 00 }\: kgf}{1 \cancel{000} \: cm^2} = 2 \: kgf \: { \:cm}^{- 1} [/tex]

Now;

[tex] \rm = \dfrac{Pressure \: Exerted \: by \: the \: Girl}{Pressure \: exerted \: by \: the \: elephant}[/tex]

[tex] = \rm \: P_1/P_2[/tex]

[tex] \implies \rm\cfrac{25 \: kgf \: \: cm {}^{ - 2} }{2 \: kgf \: cm {}^{ - 2} } = \rm\cfrac{25 \: \cancel{kgf \: \: cm {}^{ - 2}} }{2 \: \cancel{ kgf \: cm {}^{ - 2}} } = \boxed{12.5} [/tex]

Thus, the girl's pointed heel sandals exert 12.5 times more pressure P than the pressure P exerted by the elephant.

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