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Sagot :
Answer:
50π m³ or 157 m³ (rounded to nearest cubic meter)
Explanation:
[tex]\sf volume \ of \ cone \ : \ \dfrac{1}{3} \pi (radius)^2 (height)[/tex]
Here Given:
- Radius: 5 meters
- Height: 6 meters
Volume of This Cone:
[tex]\sf \dashrightarrow \dfrac{1}{3} \pi (5)^2 (6) \ = 50 \pi \ = \ 157.079 \ m^3 \ = 157 \ m^3[/tex]
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