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Sagot :
Answer: 5/9
Solution: 2x^2+16x-10=0
According to formula: X=(-16+_sqrt(16^2-(-10•2)) / 2•2
X=5/9
Solution: 2x^2+16x-10=0
According to formula: X=(-16+_sqrt(16^2-(-10•2)) / 2•2
X=5/9
Answer:
x = 0.58 or x = -8.58 to 2 d.p.
Step-by-step explanation:
Question:
Just to write the question in a better format :
[tex]2x^{2} +16x-10 = 0[/tex]
Solve for x.
Answer:
First we Simplify this by dividing everything by 2:
[tex]2x^{2} +16x-10 = 0[/tex] ÷ 2 :
[tex]x^{2} +8x-5 = 0[/tex]
Now we use the quadratic formula :
[tex]x = \frac{-b+/-\sqrt{b^{2} -4ac} }{2a}[/tex] (side note: +/- is meant to be ±)
Now we substitute a with 1, b with +8 and c with -5:
[tex]x = \frac{-8+/-\sqrt{8^{2} -4(1)(-5)} }{2(1)}[/tex] [tex]x = \frac{-8+/-\sqrt{64+20} }{2}[/tex] [tex]x = \frac{-8+/-\sqrt{84} }{2}[/tex]
The surd [tex]\sqrt{84}[/tex] = 2[tex]\sqrt{21}[/tex] So :
x = -8± 2√21 /2
x = -4 ±√21
This is our answer . Remember it is two answers in 1.
x = -4 +√21 and x = -4 -√21
x = 0.58257569495 or x = -8.58257569496
x = 0.58 or x = -8.58 to 2 d.p.
Hope this helped and brainliest please
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