Answered

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At what displacement from equilibrium is the speed of SHO half the maximum value?

Sagot :

Answer:

X = A sin ω t      is the simplest equation for SH

V = ω A cos ω t   describes the velocity where    ω A is the maximum speed

cos ω t = 1/2       describes 1/2 the maximum speed

then ω t = 60 deg      (cos 60 = 1/2)

X = A sin 60   will then be the displacement at 1/2 the maximum speed

or X = .866 A = 3^1/2 / 2 A

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