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Please Solve Quickly class=

Sagot :

TPS95

Area of a circle = πr^2

Area of a sector with angle x° = (x/360) πr^2

For the smaller sector,

x = 30°

r = 6 in

Required area of sector = (30/360) × π × 6^2 = 9.424 in^2

To the nearest hundreth, Area = 9.42 in^2