miamartin5287
Answered

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please solve quickly ​

Please Solve Quickly class=

Sagot :

TPS95

Area of a circle = πr^2

Area of a sector with angle x° = (x/360) πr^2

for the smaller sector,

x = 80°

r = 8 m

Required area of sector = (80/360) × π × 8^2 = 44.68 m^2

To the nearest tenth, Area = 44.68 m^2

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