nanaasantewaa67
Answered

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(c) The average age of a family of eight is 30 years. The average age of the six children in the family is 19 years. If the mother is four years younger than the father, calculate the age of the father.​

Sagot :

devishri1977

Answer:

Father's age = 65 years

Step-by-step explanation:

Let the age of father = x years

Age of mother           = (x - 4) years

         

[tex]\sf Average = \dfrac{Sum \ of \ all \ the \ data}{number \ of \ data}\\\\\boxed{\text{Sum of all data =average * number of data}}[/tex]

  Average age of six children =  19 years  

       Sum of age of 6 children = 19 *6 = 114 years      

Average of all 8 members = 30 years

Sum of age of all members = 30*8 = 240 years

sum of age of 6 children + father's age + mother's age = sum of all age of members

114 + x + x -4  = 240

        110 + 2x = 240

                  2x = 240 -110

                  2x = 130

                    x = 130/2

                    x = 65 years

Father's age = 65 years

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