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What is the slope of a line perpendicular to the line whose equation is 18x+3y=81 Fully simplify your answer.

Sagot :

Answer:

slope = [tex]\frac{1}{6}[/tex]

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

18x + 3y = 81 ( subtract 18x from both sides )

3y = - 18x + 81 ( divide the terms by 3 )

y = - 6x + 27 ← in slope- intercept form

with slope m = - 6

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-6}[/tex] = [tex]\frac{1}{6}[/tex]

kh5858962

Answer: m = [tex]\frac{1}{6}[/tex]

Step-by-step explanation:

Find the slope of the line that is perpendicular to 18x + 3y = 81 :: m = 1/6

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