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A 2.36-gram sample of NaHCO3 was completely decomposed in an experiment.
2NaHCO3 → Na2CO3 + H2CO3
In this experiment, carbon dioxide and water vapors combine to form H2CO3.
After decomposition, the Na2CO3 had a mass of 1.57 grams.
A. Determine the mass of the H2CO3 produced.
B. Calculate the percentage yield of H2CO3 for the reaction. Show your work or
describe the calculation process in detail.

Sagot :

Medunno13

Answer:

Explanation:

a) The mass of the reactants is 2.36 grams, and the mass of the products is 1.57 grams plus the mass of the carbonic acid. Thus, using the law of conservation of mass, we get the mass of the carbonic acid is 2.36 - 1.57 =  0.79 grams.

b) The gram-formula mass of sodium bicarbonate is 84.006 g/mol, meaning that 2.36/84.006 = 0.028 moles were consumed. Thus, this means that in theory, 0.014 moles of carbonic acid should have been produced, which would have a mass of (0.014)(62.024)=0.868 grams. Thus, the percentage yield is (0.79)/(0.868) * 100 = 91%

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