Answered

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Rosa's dog had three puppies. After a few months, she measured the weight of the four dogs. The weights were 16 pounds, 18.5 pounds, 60 pounds, and 19.5 pounds. Part A Which of the four weights is an outlier? And Part B is How much greater is the mean weight of the four dogs than the mean weight of three dogs without the outlier?

Sagot :

wolypoly

Answer:

Part A: The outlier is the 60 lbs dogs, because this dog disrupts the common pattern amongst the others, therefore it is an outlier.

Part B: The mean of all 4 dogs is is 28.5, and the mean of the 3 dogs without an outlier is 13.5. This means the difference is 15, hence 28.5-13.5=15

Step-by-step explanation:
part A, 60 pounds is the outlier, as it is the only one which is a very far number from the others
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