Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Use the quadratic formula to solve. Round to the nearest tenth if necessary.
2x^2 -3x -7 = 0

Sagot :

reyloforlife

The quadratic formula is:

[tex]\frac{-b + \sqrt{b^2 - 4ac} }{2a}[/tex] and  [tex]\frac{-b - \sqrt{b^2 - 4ac} }{2a}[/tex]

In this case, a = 2, b = -3, and c = -7

So, we can plug in the numbers to get:

  [tex]\frac{-(-3) + \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)}[/tex] and    [tex]\frac{-(-3) - \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)}[/tex]

Simplifying, we get:

    [tex]\frac{3 + \sqrt{65} }{4}[/tex] and   [tex]\frac{3 - \sqrt{65} }{4}[/tex]

You need to use a calculator to find what these would be in decimal form. The answer, rounded to the nearest tenth, is: x = 2.8, x = -1.3

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.