Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

find the error (-8x^2y^2)^2= -64x^4y^4

Sagot :

Answer:

[tex](-8)^2\neq-64[/tex]

Step-by-step explanation:

Using the distributive property to expand, we have

[tex](-8x^2y^2)^2=(-8)^2(x^2)^2(y^2)^2.[/tex]

Squaring each term, we have

[tex](-8x^2y^2)^2=64x^4y^4.[/tex]

The mistake was that [tex]8^2=64,[/tex] not [tex]-64.[/tex] Using the fact that [tex]8^2=64,[/tex] the right answer would be

[tex]\boxed{64x^4y^4}[/tex].

genan

Answer:

64 shouldnt be negative anymore

Step-by-step explanation:

(-8x^2y^2)^2 = -64x^4y^4

when exapnding the left side it would be...

(-8x^2y^2)^2

Apply exponent rule (-a)^n = a^n

→ (8x^2y^2)^2  

→ (8^2)(x^2)^2

→ (8^2) = 64

→ 64(x^2)^2 = 64x^4

Hope this helps. Let me know if you have any questions !

Have a nice rest of you day :)

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.