Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Find y when x=14 if y varies directly with x2 and y=72 when x=6

Sagot :

luana
[tex]for\ y\ \ x^2=14^2\\ for\ y=72\ \ x^2=6^2\\\\ \frac{y}{196}=\frac{72}{36}\\ 36y=72*196\ \ | divide\ by\ 36\\ \boxed{y=392}[/tex]

The approach is to first find the value of constant of proportionality 'k'.

As y varies directly with x²

So we have

y = k x².

Now when x = 6 , y = 72

Substituting the values we get

72 = k (6)²

72 = 36 k

Dividing by 36 on both sides

2 = k

So (1) becomes

y = 2 x²

Now we need to find y when x = 14

Substituting the values in (2) we get

y = 2 ×(14)²

y = 2 × 196

y =  392

Hence y = 392 when x = 14.

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.