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Please help me solve the equation
3x+10y=48
7x+4y=54

Sagot :

deathstrike001
3x+10y=48
7x+4y=54


multiply the first equation by 2 and the 2nd equation by 5 to remove y
6x+20y=96
35x+20y=270
29x=174
x=6

substitute to any equation
7x+4y=54
42+4y=54
4y=12
y=3

the value of x is 6 and the value of y is 3
zidanethernandez8

Answer: x=36/7

               y=9/2

Step-by-step explanation:

1 Solve for yy in 3+10y=483+10y=48.

y=\frac{9}{2}y=

​2

​

​9

​​

2 Substitute y=\frac{9}{2}y=

​2

​

​9

​​  into 7x+4y=547x+4y=54.

7x+18=547x+18=54

3 Solve for xx in 7x+18=547x+18=54.

x=\frac{36}{7}x=

​7

​

​36

​​

4 Therefore,

\begin{aligned}&x=\frac{36}{7}\\&y=\frac{9}{2}\end{aligned}

​

​

​​

​x=

​7

​

​36

​​

​y=

​2

​

​9

​​

​​

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