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Find f(5)+j(-2) if f(x)=12-3x ind j(x)=x² + 4x − 1

Sagot :

The value of the expression f(5) + j(-2)  is -8 where f(x)=12-3x and j(x)=x² + 4x - 1

How to solve the equation?

The expression is given as:

f(5) + j(-2)

Where f(x)=12-3x and j(x)=x² + 4x - 1

Calculate f(5) and j(-2)

f(5)= 12 - 3(5) = -3

j(-2) = (-2)² + 4(-2) - 1 = -5

So, we have:

f(5) + j(-2)  = -3 - 5

Evaluate

f(5) + j(-2)  = -8

Hence, the value of the expression f(5) + j(-2)  is -8

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