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Help me please!!! 10 points!!

Help Me Please 10 Points class=

Sagot :

Answer:

2√3

Step-by-step explanation:

The shown triangle is a 30-60-90 special right triangle due to the right angle and the thirty degree angle(the other angle has to be 60 degrees).

The hypotenuse of a 30-60-90 triangle is twice the leg opposite the 30 angle. The leg opposite the 30 degree angle is √3, so x would be 2√3.

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve for x ~

We can apply Trigonometric ratios here, since the given triangle is a right angled triangle

so,

[tex]\qquad \sf  \dashrightarrow \: \sin(30) = \dfrac{ \sqrt{3} }{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{2} = \dfrac{ \sqrt{3} }{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 2 \times \sqrt{3} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 2 \sqrt{3} [/tex]

i hope you you understood

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