Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
[tex] \textsf{\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \:(2 {}^{ \frac{2}{x} } ) \sdot(2 {}^{ \frac{4}{x} } ) = 2 {}^{12} [/tex]
[tex]\qquad \sf \dashrightarrow \:(2 {}^{ \frac{2}{x} + \frac{4}{x} } ) = 2 {}^{12} [/tex]
[tex]\qquad \sf \dashrightarrow \:(2 {}^{ \frac{6}{x} } ) = 2 {}^{12} [/tex]
Now, since the base on both sides are equal, therefore their exponents are equal as well ~
[tex]\qquad \sf \dashrightarrow \: \dfrac{6}{x} = 12[/tex]
[tex]\qquad \sf \dashrightarrow \:x = \dfrac{6}{12} [/tex]
[tex]\qquad \sf \dashrightarrow \:x = \dfrac{1}{2} [/tex]
or
[tex]\qquad \sf \dashrightarrow \:x = 0.5[/tex]
Hope you got the required Answer ~
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.