Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Given line PQ bisects line RS, LR=LS
Prove: Triangle PQR= Triangle PQS

Given Line PQ Bisects Line RS LRLS Prove Triangle PQR Triangle PQS class=

Sagot :

aklee18oo

Answer:

See Below

Step-by-step explanation:

Since PQ is perpendicular to RS, the angles PQR and PQS would be right angles, and right anglers are congruent, so <PQR ≅ <PQS. We are given that <R and <S are the same length, so they are congruent(<R ≅ <S). Since PQ is included in both triangles and it is the same length as itself(PQ ≅ PQ).

We have three congruent parts, two angles and one side. Therefore, using AAS, ΔPQR ≅ ΔPQS

Answer:

See below ~

Step-by-step explanation:

Given :

⇒ PQ ⊥ RS

⇒ ∠R = ∠S

===============================================================

Solving :

⇒ PQ = PQ (common side)

⇒ ∠R = ∠S (given)

⇒ ∠PQS = ∠PQR = 90° (⊥ bisector forms equal right angles)

⇒ ΔPQR ≅ ΔPQS (by ASA congruence)

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.