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Help pls!
Which rational function has zeros at x = -1 and x = 6 ?

Help Pls Which Rational Function Has Zeros At X 1 And X 6 class=

Sagot :

Answer:

[tex]f(x) = \frac{x^{2} -5x-6}{x^{2} -4}[/tex]

Step-by-step explanation:

Let's factorize the 1st option :

⇒ [tex]f(x) = \frac{x^{2} -5x-6}{x^{2} -4}[/tex]

⇒ [tex]f(x) = \frac{x^{2}+x-6x-6 }{(x+2)(x-2)}[/tex]

⇒ [tex]f(x) = \frac{(x+1)(x-6)}{(x+2)(x-2)}[/tex]

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Finding the zeros :

⇒ Factors of numerator should be equated to 0

  1. x + 1 = 0 ⇒ x = -1
  2. x - 6 = 0 ⇒ x = 6

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Solution :

[tex]f(x) = \frac{x^{2} -5x-6}{x^{2} -4}[/tex]

Answer:

first option

Step-by-step explanation:

the zeros are determined by the numerator of the rational function.

given that the zeros are x = - 1 and x = 6 , then the corresponding factors are

(x + 1) and (x - 6) , that is

(x + 1)(x - 6) ← expand using FOIL

= x² - 5x - 6

the rational function is then

f(x) = [tex]\frac{x^2-5x-6}{x^2-4}[/tex]

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