alexbrelsford08
Answered

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Aakesh has two bags of marbles. The first bag contains 6 red marbles, 4 blue
marbles, and 5 green marbles. The second bag contains 3 red marbles, 1 blue
marble, and 5 green marbles. Aakesh will randomly select one marble from
each bag.
What is the probability that Aakesh will select a green marble from each bag?


A. 4/9

B.1/3

C. 5/9

D. 5/27

Sagot :

The answer for the 1st bag is option B = 1/3

The answer for the 2nd bag is option C = 5/9

Number of marbles in 1st bag - 15 (6 red, 4 blue & 5 green)

Number of marbles in 2nd bag - 9 (3 red, 1 blue & 5 green)

The formula of probability = Total number of events in the outcome /total number of outcomes.

Now the probability that Aakesh will select a green marble from the 1st bag is 5(green marbles)/15(total number of marbles in 1st bag)

That is 5/15=1/3

Now the probability that Aakesh will select a green marble from the 2nd bag is 5(green marbles)/9(total number of marbles in 1st bag)

That is 5/9

To know more about probability go to -  https://brainly.in/question/17157610?msp_poc_exp=6

leac16

•ω• Hewo fren!

☆☆●◉✿ Answer:✿◉●☆☆

C.) 5/9

☆☆●◉✿Step-by-step explanation:✿◉●☆☆

First we must figure out how many marbles we have in total.

Meaning we will add all of the marbles together in bag one and then bag two.

Bag one: 6+4+5= 15

Bag two: 3+1+5= 9

Total= 24 marbles

Now we will try and figure out how many greens are in the total amount of marbles.

Amount of green marbles in bag one: 5

Amount of green marbles in bag two: 5

Total green marbles: 10

The third and final step!

10/24 is the amount of green marbles so the answer is C!

Hope I helped~! >w<

→⇒brainliest please? ∑(OΔO )♥♥︎

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