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Find the minimum distance between the point (-3,2) and the line y = -x + 1
(Enter an exact answer with a square root.)


Find The Minimum Distance Between The Point 32 And The Line Y X 1 Enter An Exact Answer With A Square Root class=

Sagot :

The minimum distance  between the point(-3,2) and the line y = -x + 1  is [tex]\sqrt{2}[/tex] units.

What is a line segment?

The line that joins  two points on a cartesian plane is a line segment.

Analysis:

The formula for calculating distance between a line and a point is

d = [tex]\frac{Ax1 + By1 + c}{\sqrt{A^{2} + B^{2} } }[/tex]

where A = coefficient of x term of the line, B = coefficient of y in the line and C is the constant term of the line.

x1 and y1 are coordinates of the point.

for the line y = -x + 1 which is  = y + x -1 = 0, A = 1, B = 1, C = -1, x1 = -3, y = 2
d = [tex]\frac{1(-3) + 1(2) + (-1)}{\sqrt{(-3)^{2} + 2^{2} } }[/tex]= [tex]\sqrt{2}[/tex] units

In conclusion, the distance between the point and the line is  [tex]\sqrt{2}[/tex] units

Learn more about distance between line segments: brainly.com/question/2437195

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