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Sagot :
Answer:
¥4630.50
Step-by-step explanation:
Compound Interest Formula
[tex]\large \text{$ \sf A=P(1+\frac{r}{n})^{nt} $}[/tex]
where:
- A = final amount
- P = principal amount
- r = interest rate (in decimal form)
- n = number of times interest applied per time period
- t = number of time periods elapsed
Given:
- P = 4000
- r = 10% = 0.1
- n = 2
- t = 1.5
Substitute the given values into the formula and solve for A:
[tex]\implies \sf A=4000\left(1+\dfrac{0.1}{2}\right)^{2 \times 1.5}[/tex]
[tex]\implies \sf A=4000\left(1.05\right)^{3}[/tex]
[tex]\implies \sf A=4630.50[/tex]
Answer:
¥4630.50
Step-by-step explanation:
Here,
- P = ¥4000
- n = 1 1/2 = 3/2 years
- r = 10% per annum
ATQ, as well,the interest is payable in half-yearly.
We know that,
- [By this formula,it could easily solved]
[tex] \boxed{\rm \: A = P \bigg(1+ \cfrac{ \cfrac{r}{2} }{100} \bigg) {}^{2n} }[/tex]
Substitute the values
[tex]A = 4000 \bigg(1 + \cfrac{5}{100} \bigg) {}^{2 \times \frac{3}{2} } [/tex]
Now solve.
[tex]A = 4000 * (21/20)^3[/tex]
[tex] \implies \: A = 4000 \times \cfrac{21}{20} \times \cfrac{21}{20} \times \cfrac{21}{20} = \cfrac{21 \times 21 \times 21}{2} [/tex]
[tex] \implies \: A = \: \yen \: 4630.50[/tex]
Hence,the sum of ¥ 4000 will be amounted to ¥4630.50 in 1 1/2 years.
[tex] \rule{225pt}{2pt}[/tex]
This question arises:Why we used that formula?
Reason:
The compound interest is calculated half-yearly, the formula changes a little.In this case for r we write r/2 and for n we write 2n because a rate of r% per annum is r/2% half-yearly and n years = 2n half year So this is the reason.
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