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y= x^2-4x+3 in vertex form

Sagot :

Answer:

[tex]y=(x-2)^2-1[/tex]

Step-by-step explanation:

Complete the square

[tex]y=x^2-4x+3\\\\y+1=x^2-4x+3+1\\\\y+1=x^2-4x+4\\\\y+1=(x-2)^2\\\\y=(x-2)^2-1[/tex]

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