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what is the equation of the line that contains point (2, -6) and has a slope of -2

y= -2x + 10
y= -2x + 2
y= -2x - 2
y= -2x -10

Sagot :

Answer:

y=-2x+10

Step-by-step explanation:

i graphed it i graphed all of them

Answer:

y-2x-2

Step-by-step explanation:

The way I would do this is by first using the information given and making an equation in point-slope form, before bringing it to y=mx+b.

We know that the slope is -2, and we have a point, (2,-6). The formula for equations in point slope form is [tex]y-y_{1} =m(x-x_{1} )[/tex]. So, we can insert the given information into this formula to get [tex]y+6=-2(x-2)[/tex].

Next, we distribute the slope to the the parenthesis to get [tex]y+6=-2x+4[/tex]

Then, we subtract 6 from both sides to get [tex]y=-2x-2[/tex]

Since this equation is now in the form [tex]y=mx+b[/tex], the answer is [tex]y-2x-2[/tex]

Hope this helps! :)