Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A new computer loses 1/2 of its value every year. Which graph could represent the relationship between the year and the computer’s value?

SOMEONE HELP PLS, YOU’LL GET FREE EASY POINTS IF THE ANSWER IS RIGHT!!!!


A New Computer Loses 12 Of Its Value Every Year Which Graph Could Represent The Relationship Between The Year And The Computers Value SOMEONE HELP PLS YOULL GET class=

Sagot :

Let's first consider: the fact that a new computer loses 1/2 of its value

 ⇒ third choice and fourth choice are eliminated

    ⇒ because of the graph project the computer's value as growing over  

         years

Now let's try to set up an equation:

After 1st year ⇒ Computer's value = [tex]total_.value*\frac{1}{2}[/tex]

After 2nd year ⇒ Computer's value = [tex]total_.value*\frac{1}{2}*\frac{1}{2}=total_.value*(\frac{1}{2} )^2[/tex]

After 3rd year ⇒ Computer's value =[tex]total_.value*\frac{1}{2}*\frac{1}{2}* \frac{1}{2}=total_.value*(\frac{1}{2})^3[/tex]

     

 ..... (Hopefully you see a pattern)

After x year ⇒ Computer's value = [tex]total_.value*(\frac{1}{2})^x[/tex]

Therefore, the equation is: [tex]total_.value*(\frac{1}{2})^x[/tex]

  ⇒that means the graph has to exponentially decreasing as it has

     an exponent (meaning the function is exponential) and a base less

     than 1 (meaning that the function is decreasing)

Answer: Choice (1)

Hope that helps!

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.