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Sagot :
Using the t-distribution, it is found that the 95% confidence interval for the population mean rating for Miami is (5.73, 6.95).
What is a t-distribution confidence interval?
The confidence interval is:
[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]
In which:
- [tex]\overline{x}[/tex] is the sample mean.
- t is the critical value.
- n is the sample size.
- s is the standard deviation for the sample.
The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 50 - 1 = 49 df, is t = 2.0096.
Considering the given sample, the other parameters are given as follows:
[tex]\overline{x} = 6.34, s = 2.16, n = 50[/tex]
Hence, the bounds of the interval are:
[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 6.34 - 2.0096\frac{2.16}{\sqrt{50}} = 5.73[/tex]
[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 6.34 + 2.0096\frac{2.16}{\sqrt{50}} = 6.95[/tex]
More can be learned about the t-distribution at https://brainly.com/question/16162795
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