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Two sides and the included angle of triangle were measured as under
A = 757.64 +0.045 m
B = 946.70+ 0.055 m
C = 54°18+25"


Sagot :

Lanuel

Based on the calculations, the area of this triangle is equal to 290,136.87 m².

Given the following data:

  • Side A = 757.64 +0.045 m.
  • Side B = 946.70+ 0.055 m.
  • Angle, C = 54°18'25"

How to calculate the area of this triangle?

Mathematically, the area of a triangle can be calculated by using this formula:

Area = 1/2 × b × h

Where:

  • b is the base area.
  • h is the height.

In this scenario, the area of this triangle is given by:

Area = 1/2 × a × b × sinC

Substituting the given parameters into the formula, we have:

Area = 1/2 × 757.64 × 946.70 × sin(54°18'25")

Area = 580,273.74/2

Area = 290,136.87 m².

Next, we would determine the probable error of the area by using this formula:

[tex]PE_A = \pm k \sqrt{PE} \\\\PE_A = \pm \frac{1}{2} \times sinC \sqrt{(aPE_b)^2 + (bPE_a)^2 } \\\\PE_A = \pm \frac{1}{2} \times sin(54^{\circ}18'25") \times \sqrt{(757.64 \times 0.045)^2 + (946.70 \times 0.055)^2 } \\\\PE_A = \pm 0.4045 \times \sqrt{1,162.39 +2,711.12}\\\\PE_A = \pm 0.4045 \times \sqrt{3,873.51}\\\\PE_A = \pm 0.4045 \times 62.2375\\\\PE_A = \pm25.1751 \;m^2[/tex]

Therefore, probable error of the area is equal to ±25.1751 m².

Read more on area of triangle here: brainly.com/question/21917592

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Complete Question:

Two sides and the included angle of a triangle were measured and the probable error of each value were computed as follows:

A = 757.64 +0.045 m

B = 946.70+ 0.055 m

C = 54°18'25"

Determine the area of the triangle and the probable error of the area.