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Sagot :
The total number of possible PINs' that you can make is; 74,088,000 PINS
How to solve probability combinations?
Each of the first 3 letters can be chosen from the 21 letters since 5 vowels cannot be used, {A, B, C, …, U, V, W}.
Thus, number of possible choices = 21³ possible choices.
The first 3 digits can be any number from {0, 1, 2, …, 9}, so there are 10³ choices.
The last digit cannot be 0 or 9, so you can select from {1, 2, 3, …, 8} which gives 8 choices.
Then the total number of PINs that you can make is; 21³ × 10³ × 8 = 74,088,000
Read more about Probability Combination at; https://brainly.com/question/4658834
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