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Two balls are drawn without replacement from a box containing 2black and 3 red balls. What is the probability of drawing a black ball on the second draw? Draw a tree diagram

Sagot :

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The probability that the second ball drawn is black is 4/10 = 2/5

How to find the probability?

There are two cases. The case where the first ball is red is the first one.

The probability of drawing a red ball is equal to the quotient between the number of red balls and the total number of balls.

p = 3/5

Then, the probability of drawing a black ball in the second attempt is computed in the same way, but because we already drew a ball, now the total number of balls is 4, so we have:

q = 2/4 = 1/2.

So the joint probability is:

P = (3/5)*(1/2) = 3/10.

Then we have the case where both balls are black, the probabilities now are:

p = 2/5

q = 1/4

So the joint probability is:

P = (2/5)*(1/4) = 1/10

The total probability is the sum of the two above:

probability = 3/10 + 1/10 = 4/10.

The probability that the second ball drawn is black is 4/10 = 2/5

If you want to learn more about probability:

https://brainly.com/question/251701

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