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Sagot :
The probability that exactly 800 chips are acceptable is less than 0.000001
How to determine the probability?
The given parameters are:
- Sample, n = 3000
- Percentage acceptable, p = 72%
- Acceptable chips, x = 800
The binomial probability is represented as:
[tex]P(x) = ^nC_x * p^x * (1- p)^{n - x}[/tex]
So, we have:
[tex]P(300) = ^{3000}C_{800} * (72\%)^{800} * (1- 72\%)^{3000 - 800}[/tex]
The data values are large.
So, we use a statistical calculator to evaluate the expression
Using the calculator, we have:
P(300) < 0.000001
Hence, the probability that exactly 800 chips are acceptable is very small i.e. less than 0.000001
Read more about probability at:
https://brainly.com/question/25870256
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