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Write the equation of the circle in general form. Show your work.

Write The Equation Of The Circle In General Form Show Your Work class=

Sagot :

Answer:

x^2+2x+y^2−2y−7=0

Step-by-step explanation:

The method from converting to standard to general is very simple

this equation in standard form would be

(x+1)^2+(y-1)^2=9

This is because whatever the center of the circle is, you take the negative/positive version of that number

The center is at -1, 1.  So it would flip to be put into the equation as 1, -1.

9 is the radius^2.

The radius is 3.

To convert to general form you just simplify

x^2+1+2x = (x+1)^2

y^2 + 1 -2y = (y-1)^2

x^2 - 2x + y^2 - 2y + 2 = 9

get the nine on the left side

x^2 -2x +y^2 - 2y 2 - 9 = 0

x^2+2x+y^2−2y−7=0

Give brainliest, please!

Hope this helps :)

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