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Solve the following inequality using both the graphical and algebraic approach: 8 minus x greater-than-or-equal-to 5 (8 minus x) Graph A On a coordinate plane, a line goes through (0, 8) and (8, 0). Another line goes through (8, 0) and (7, 10). Graph B On a coordinate plane, a horizontal line is at y = 5 and another line goes through (8, 0) and (0, negative 8). a. x greater-than-or-equal-to 8 Graph A b. x less-than-or-equal-to 8 Graph A c. x greater-than-or-equal-to 8 Graph B d. x less-than-or-equal-to 8 Graph B

Sagot :

azikennamdi

The given inequality (8 - X ≥ 5(8 - x)) is solved using graphs method and the result is (Option A); that is x ≥ 8 Graph A.

What is the solution using algebraic approach?

The inequality is given as: 8-x≥5(8-x)

The next step algebraically is to open the brackets. Hence,

8-x ≥ 40 -5x

Next, we collect like terms

= -x+5x ≥ 40-8

= 4x ≥ 32

Make x the subject of the statement by dividing both sides with 4

= x ≥ 8


Learn more about inequalities at:
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